제가 채팅어플에서 대화하는 화면을 ListView로 만들고 있습니다.
public class chat3 extends Activity {
String streammsg = "", Client_id, server_ip, server_port ;
ListView showText;
EditText editText_massage;
Button Button_send;
Handler msghandler;
SocketClient client;
ReceiveThread receive;
SendThread send;
Socket socket;
PipedInputStream sendstream = null;
PipedOutputStream receivestream = null;
LinkedList<SocketClient> threadList;
ArrayAdapter<String> adapter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.chat3);
showText = (ListView) findViewById(R.id.showText_ListView);
adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1);
showText.setAdapter(adapter);
editText_massage = (EditText) findViewById(R.id.editText_massage);
Button_send = (Button) findViewById(R.id.Button_send);
threadList = new LinkedList<chat3.SocketClient>();
Intent y;
y = getIntent();
server_ip = y.getStringExtra("ip");
server_port = y.getStringExtra("port");
Client_id = y.getStringExtra("id");
client = new SocketClient(server_ip,server_port);
threadList.add(client);
client.start();
// ReceiveThread를통해서 받은 메세지를 Handler로 MainThread에서 처리(외부Thread에서는 UI변경이불가)
msghandler = new Handler() {
@Override
public void handleMessage(Message hdmsg) {
if (hdmsg.what == 1111) {
adapter.add(hdmsg.obj.toString() + "\n");
//showText.add(hdmsg.obj.toString() + "\n");
}
}
};
//전송 버튼 클릭 이벤트
Button_send.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
//SendThread 시작
if (editText_massage.getText().toString() != null) {
send = new SendThread(socket);
send.start();
//시작후 edittext 초기화
editText_massage.setText("");
}
}
});
}
class SocketClient extends Thread {
boolean threadAlive;
String ip;
String port;
String mac;
//InputStream inputStream = null;
OutputStream outputStream = null;
BufferedReader br = null;
private DataOutputStream output = null;
public SocketClient(String ip, String port) {
threadAlive = true;
this.ip = ip;
this.port = port;
}
@Override
public void run() {
try {
// 연결후 바로 ReceiveThread 시작
socket = new Socket(ip, Integer.parseInt(port));
//inputStream = socket.getInputStream();
output = new DataOutputStream(socket.getOutputStream());
receive = new ReceiveThread(socket);
receive.start();
//mac주소를 받아오기위해 설정
WifiManager mng = (WifiManager) getSystemService(WIFI_SERVICE);
WifiInfo info = mng.getConnectionInfo();
mac = info.getMacAddress();
//mac 전송
output.writeUTF(mac);
} catch (IOException e) {
e.printStackTrace();
}
}
}
class ReceiveThread extends Thread {
private Socket socket = null;
DataInputStream input;
public ReceiveThread(Socket socket) {
this.socket = socket;
try{
input = new DataInputStream(socket.getInputStream());
}catch(Exception e){
}
}
// 메세지 수신후 Handler로 전달
public void run() {
try {
while (input != null) {
String msg = input.readUTF();
if (msg != null) {
Log.d(ACTIVITY_SERVICE, "test");
Message hdmsg = msghandler.obtainMessage();
hdmsg.what = 1111;
hdmsg.obj = msg;
msghandler.sendMessage(hdmsg);
Log.d(ACTIVITY_SERVICE,hdmsg.obj.toString());
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
class SendThread extends Thread {
private Socket socket;
String sendmsg = editText_massage.getText().toString();
DataOutputStream output;
public SendThread(Socket socket) {
this.socket = socket;
try {
output = new DataOutputStream(socket.getOutputStream());
} catch (Exception e) {
}
}
public void run() {
try {
// 메세지 전송부 (누군지 식별하기위한 방법으로 mac를 사용)
Log.d(ACTIVITY_SERVICE, "11111");
String mac = null;
WifiManager mng = (WifiManager) getSystemService(WIFI_SERVICE);
WifiInfo info = mng.getConnectionInfo();
mac = info.getMacAddress();
if (output != null) {
if (sendmsg != null) {
output.writeUTF(mac + " : " +sendmsg);
}
}
} catch (IOException e) {
e.printStackTrace();
} catch (NullPointerException npe) {
npe.printStackTrace();
}
}
}
}
로 진행해 봤는데 화면에 처음 접속되는 안내메시지만 ListView에 출력되고 대화 내용들은 출력되지 않고 있습니다. 혹시 아래에 계속 대화내용을 입력 받아서 화면에 출력하고 싶은데 떻게 구현하면 좋을까요??
안드로이드 초보에게 도움즘주세요 ㅜㅜ
